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-16x^2+30x=9
We move all terms to the left:
-16x^2+30x-(9)=0
a = -16; b = 30; c = -9;
Δ = b2-4ac
Δ = 302-4·(-16)·(-9)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*-16}=\frac{-48}{-32} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*-16}=\frac{-12}{-32} =3/8 $
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